Multiple choiceQuestion 1 · Apply
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By the end you can calculate from equilibrium amounts in a known volume, calculate from mole fractions and a total pressure, and decide which routine a question is asking for.
Every calculation in this topic follows one of two paths.
For : amounts → concentrations (divide by volume) → substitute → answer.
For : amounts → mole fractions (divide by total moles) → partial pressures (multiply by total pressure) → substitute → answer.
In both cases the substitution step is identical; only the preparation differs.
Most lost marks in these calculations are not chemistry errors. They are these three:
Worked example: Worked example: $K_c$ from equilibrium concentrations
Hydrogen and iodine are mixed in a flask at :
Initially there is of each reactant. At equilibrium the flask contains of . Calculate .
Worked example: Worked example: $K_c$ when the volume is not 1
Nitrogen dioxide is sealed in a vessel and equilibrates:
Initially there is of . At equilibrium of remains. Calculate .
Worked example: Worked example: $K_p$ from mole fractions
At equilibrium a mixture of , and has mole fractions , and respectively. The total pressure is . Calculate for
Look at what the question supplies before deciding which constant it wants.
| Given | Use |
|---|---|
| amounts and a volume | |
| concentrations directly | |
| partial pressures | |
| mole fractions and total pressure | |
| amounts and total pressure, no volume |
If a volume is given but the question asks for , the volume is a distraction — mole fractions do not need it.
Moles can be substituted directly into a expression.
requires concentrations, so divide amounts by the volume in first.
Starting amounts are used in the expression.
Only equilibrium amounts or concentrations belong in or .
A larger volume always increases .
depends only on temperature. Changing the volume changes the mixture, not the constant.
If the value works out to , it must be wrong because should be near 1.
ranges over many orders of magnitude. simply means the equilibrium lies well to the right.
You must convert into before answering a question.
Calculate directly from partial pressures; converting between the constants is not required.