Multiple choiceQuestion 1 · Recall
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By the end you can use the angle in a semicircle and the perpendicular bisector of a chord to find the centre and equation of a circle through given points.
The key coordinate fact: two lines are perpendicular exactly when their gradients multiply to . For example, gradients and : , so lines with these gradients meet at right angles.
Circle facts you may have met before, now with coordinates. Three of them do almost all the work:
| Fact | In coordinates |
|---|---|
| Tangent ⊥ radius | gradients multiply to |
| Angle in a semicircle is | if is a diameter, |
| Perpendicular bisector of a chord passes through the centre | the centre lies on it |
Angle in a semicircle
If is a diameter of a circle and is any other point on the circle, then angle .
It works backwards too: if angle , then lies on the circle with diameter .
Why is it ? Join to the centre . Now , and are all radii, so triangles and are both isosceles. Call their base angles (at and at ) and (at and at ). The big triangle has angles , and , which add to : , so the angle at is .