CalculateQuestion 1 · Recall
Loading…
By the end you can solve inequalities such as , and harder ones such as , using both algebra and a sketch.
Modulus inequalities come in two shapes, and they behave differently.
Shape 1: the modulus is alone on the left.
Read it as "the distance from to is less than ". This works because is how far is from , with a sign; the modulus removes the sign. The answer is one interval.
Shape 2: ordinary algebra is on one side.
Here the modulus is not alone, so you cannot use the interval formula. Split the number line into cases.
Learn the geometry first. An inequality describes a region of the number line, not a single point.
| Symbol | What it means here |
|---|---|
| the centre of the interval — the point the distance is measured from | |
| the distance allowed; always for a sensible interval | |
| the unknown value you are listing | |
| and | open and closed ends: excludes the endpoint, includes it |
Being within of means being between the two points to the left and to the right of :
So the method is:
For the reverse direction the answer is two separate pieces instead of one:
The forgotten step: the direction of the inequality decides the shape of the answer. "Less than" gives the middle piece; "greater than" gives the two outer pieces.
Worked example: Example 1: the easy shape
Solve .